HC equiv CH xrightarrow[HgSO_4]{H_2SO_4} ,, x | vedclass

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(A) Step $1$: Hydration of acetylene $(HC \equiv CH)$ in the presence of $HgSO_4/H_2SO_4$ gives acetaldehyde $(CH_3CHO)$.Step $2$: Reaction of acetald

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$CH_3CH(Br)CH_3$

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(A) Step $1$: Hydration of acetylene $(HC \equiv CH)$ in the presence of $HgSO_4/H_2SO_4$ gives acetaldehyde $(CH_3CHO)$.Step $2$: Reaction of acetaldehyde with Grignard reagent $(CH_3MgBr)$ followed by hydrolysis $(HOH)$ yields isopropyl alcohol $(CH_3CH(OH)CH_3)$.Step $3$: Reaction of isopropyl alcohol with $P/Br_2$ (or $PBr_3$) results in the substitution of the hydroxyl group with bromine to form isopropyl bromide $(CH_3CH(Br)CH_3)$.

$HC \equiv CH$ $\xrightarrow[HgSO_4]{H_2SO_4} \,\,$ $\xrightarrow[HOH]{CH_3MgBr} \,\,$ $\xrightarrow{P/Br_2} (X)$; $(X)$ is

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