N_2 is found in a 1 L flask under 100 kPa p | vedclass

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(D) The total volume of the two flasks when connected is $V_{total} = 1 \ L + 3 \ L = 4 \ L$. Applying Boyle's Law $(P_1V_1 = P_2V_2)$ for each gas in

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$265$

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(D) The total volume of the two flasks when connected is $V_{total} = 1 \ L + 3 \ L = 4 \ L$. Applying Boyle's Law $(P_1V_1 = P_2V_2)$ for each gas individually: For $N_2$: $100 \ kPa 	imes 1 \ L = P_{N_2} 	imes 4 \ L$,which gives $P_{N_2} = 25 \ kPa$. For $O_2$: $320 \ kPa 	imes 3 \ L = P_{O_2} 	imes 4 \ L$,which gives $P_{O_2} = 240 \ kPa$. According to Dalton's Law of partial pressures,the total pressure $P_{total} = P_{N_2} + P_{O_2} = 25 \ kPa + 240 \ kPa = 265 \ kPa$.

$N_2$ is found in a $1 \ L$ flask under $100 \ kPa$ pressure and $O_2$ is found in another $3 \ L$ flask under $320 \ kPa$ pressure. If the two flasks are connected,the resultant pressure is $............... \ kPa$.

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