[Co(NH_3)_6]^{+2} is paramagnetic in nature d | vedclass

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Question

(A) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In $[Co(NH_3)_6]^{+2}$,the oxidation state of $Co$ is

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$3d$

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(A) The atomic number of $Co$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In $[Co(NH_3)_6]^{+2}$,the oxidation state of $Co$ is $+2$. Thus,the configuration of $Co^{+2}$ is $[Ar] 3d^7$.In the presence of $NH_3$ (a strong field ligand),the electrons in the $3d$ orbitals rearrange.For $Co^{+2}$ $(3d^7)$,the distribution is $t_{2g}^5 e_g^2$.This results in $3$ unpaired electrons in the $3d$ orbitals,making the complex paramagnetic.

$[Co(NH_3)_6]^{+2}$ is paramagnetic in nature due to the presence of unpaired $e^-$ in

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