$SnCl_2$ acts as a reducing agent because:
- A$SnCl_2$ can accept electrons readily
- B$Sn^{2+}$ is more stable than $Sn^{4+}$
- C$Sn^{4+}$ is more stable than $Sn^{2+}$
- D$Sn^{2+}$ can be easily converted to metallic tin
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