$Fe(OH)_2$ is precipitated from $Fe(II)$ solutions as a white solid but turns dark green and then brown due to the formation of:

  • A
    $Fe(OH)_2$ and $Fe(OH)_3$
  • B
    only $Fe(OH)_3$
  • C
    $Fe_2O_3 \cdot (H_2O)_n$
  • D
    $Fe_2O_3 \cdot 2H_2O$

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