CuSO_{4(aq)} xrightarrow{H_2S uparrow} M down | vedclass

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(A) The reaction of $CuSO_4$ with $H_2S$ produces a black precipitate of copper$(II)$ sulfide $(CuS)$:$CuSO_{4(aq)} + H_2S_{(g)} \rightarrow CuS_{(s)}

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$[Cu(CN)_4]^{3-}, (CN)_2$

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(A) The reaction of $CuSO_4$ with $H_2S$ produces a black precipitate of copper$(II)$ sulfide $(CuS)$:$CuSO_{4(aq)} + H_2S_{(g)} \rightarrow CuS_{(s)} (M) + H_2SO_{4(aq)}$When $CuS$ is treated with excess $KCN$,it undergoes a redox reaction where $Cu(II)$ is reduced to $Cu(I)$ and $CN^-$ is oxidized to cyanogen gas $(CN)_2$:$2CuS_{(s)} + 8KCN_{(aq)} \rightarrow 2K_3[Cu(CN)_4]_{(aq)} (N) + (CN)_{2(g)} (O) + 2K_2S_{(aq)}$Thus,the final products $N$ and $O$ are $[Cu(CN)_4]^{3-}$ and $(CN)_2$ respectively.

$CuSO_{4(aq)}$ $\xrightarrow{H_2S \uparrow} M \downarrow$ $\xrightarrow[\text{Excess}]{KCN} N + O$
Then final products $N$ and $O$ are respectively.

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$CuSO_{4(aq)}$ $\xrightarrow{H_2S \uparrow} M \downarrow$ $\xrightarrow[\text{Excess}]{KCN} N + O$Then final products $N$ and $O$ are respectively.