In the hydrides of the nitrogen group,the H-M | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) As we move down the group,the electronegativity of the central atom decreases. Consequently,the bond pair of electrons moves away from the central

Vedclass · Accepted Answer

Almost pure $p$-orbitals are used in $M-H$ bonding.

Vedclass · Answer

(B) As we move down the group,the electronegativity of the central atom decreases. Consequently,the bond pair of electrons moves away from the central atom. This results in a decrease in the $H-M-H$ bond angle,which approaches $90^o$. This indicates that the $M-H$ bonds involve almost pure $p$-orbitals,as there is very little hybridization.

In the hydrides of the nitrogen group,the $H-M-H$ bond angle gradually approaches $90^o$ as we move from $N$ to $Sb$. This indicates that gradually.....

Similar Questions

For the properties mentioned,the correct trend for the different species is in

The structure of white phosphorus is ........ .

Extra pure $N_2$ can be obtained by heating :-

Which colorless gas has a smell like rotten fish?

What happens when $PCl_{5}$ is heated?

Vedclass Test Series

Exam Paper Generator

Online Exam Module