In the reaction $HNO_3 + HF \to H_2NO_3^+ + F^-$,which species acts as a base?
- A$HF$
- B$HNO_3$
- C$HF$ and $HNO_3$
- DNone of these
Explore More
Similar Questions
Identify a species which is not a Bronsted acid but a Lewis acid.
Which of the following pairs of species is used in the preparation of antacid medicines?
Medium
View SolutionIdentify the conjugate acid-base pair from the following equilibrium reaction.
$HSO_{3(aq)}^{-} + H_3O_{(aq)}^{+} \rightleftharpoons H_2SO_3 + H_2O$
$HSO_{3(aq)}^{-} + H_3O_{(aq)}^{+} \rightleftharpoons H_2SO_3 + H_2O$
Match the following:
List-$I$ (Acid) List-$II$ ($K_a$ - Ionization Constant) $A$. $HCN$ $I$. $6.8 \times 10^{-4}$ $B$. $H_2C_2O_4$ $II$. $8.9 \times 10^{-8}$ $C$. $H_2S$ $III$. $4.9 \times 10^{-10}$ $D$. Niacin $IV$. $5.6 \times 10^{-2}$ $V$. $1.5 \times 10^{-5}$
The correct match is:
| List-$I$ (Acid) | List-$II$ ($K_a$ - Ionization Constant) |
| $A$. $HCN$ | $I$. $6.8 \times 10^{-4}$ |
| $B$. $H_2C_2O_4$ | $II$. $8.9 \times 10^{-8}$ |
| $C$. $H_2S$ | $III$. $4.9 \times 10^{-10}$ |
| $D$. Niacin | $IV$. $5.6 \times 10^{-2}$ |
| $V$. $1.5 \times 10^{-5}$ |
The correct match is:
The conjugate base of hydrazoic acid is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo