The bond dissociation energies of F_2, Cl_2, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The bond strength is directly proportional to the bond dissociation energy. Lower bond dissociation energy indicates a weaker bond. Comparing the

Vedclass · Accepted Answer

$I_2$

Vedclass · Answer

(D) The bond strength is directly proportional to the bond dissociation energy. Lower bond dissociation energy indicates a weaker bond. Comparing the given values: $F_2 (155 \ kJ \ mol^{-1})$,$Cl_2 (244 \ kJ \ mol^{-1})$,$Br_2 (193 \ kJ \ mol^{-1})$,and $I_2 (151 \ kJ \ mol^{-1})$. Since $I_2$ has the lowest bond dissociation energy of $151 \ kJ \ mol^{-1}$,it has the weakest bond.

The bond dissociation energies of $F_2, Cl_2, Br_2$ and $I_2$ are $155, 244, 193$ and $151 \ kJ \ mol^{-1}$ respectively. Which of these has the weakest bond?

Similar Questions

Which of the following is not oxidised by $MnO_2$?

Which of the following is the strongest oxidizing agent?

Which of the following reactions would be incorrect?

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$\underline{Cl}F_5 + H_2O \longrightarrow HClO_3 + HF$

$O_2$ is formed in the hydrolysis of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module