What is the product formed when XeF_4 reacts | vedclass

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(C) The hydrolysis of $XeF_4$ is a violent reaction. The balanced chemical equation is: $6XeF_4 + 12H_2O 	o 2Xe + 4XeO_3 + 24HF + 3O_2$. However,in m

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$Xe + HF + XeO_3 + O_2$

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(C) The hydrolysis of $XeF_4$ is a violent reaction. The balanced chemical equation is: $6XeF_4 + 12H_2O 	o 2Xe + 4XeO_3 + 24HF + 3O_2$. However,in many simplified contexts,the reaction is represented as: $2XeF_4 + 3H_2O 	o Xe + XeO_3 + 6HF + 0.5O_2$. Given the options provided,the reaction products include $Xe$,$XeO_3$,$HF$,and $O_2$.

What is the product formed when $XeF_4$ reacts violently with water?

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