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(C) The oxidizing power of halogens follows the order $F_2 > Cl_2 > Br_2 > I_2$. Thus,option $(A)$ is correct.The electron gain enthalpy of halogens f

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$F_2 > Cl_2 > Br_2 > I_2$: Bond dissociation energy

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(C) The oxidizing power of halogens follows the order $F_2 > Cl_2 > Br_2 > I_2$. Thus,option $(A)$ is correct.The electron gain enthalpy of halogens follows the order $Cl_2 > F_2 > Br_2 > I_2$. The value for $F_2$ is less negative than $Cl_2$ due to its small size and inter-electronic repulsions. Thus,option $(B)$ is incorrect.The bond dissociation energy of halogens follows the order $Cl_2 > Br_2 > F_2 > I_2$. The $F-F$ bond is weaker due to high inter-electronic repulsion between lone pairs. Thus,option $(C)$ is incorrect.The electronegativity of halogens follows the order $F_2 > Cl_2 > Br_2 > I_2$. Thus,option $(D)$ is correct.Since the question asks for the arrangement that does not represent the correct trend,both $(B)$ and $(C)$ are incorrect. However,in standard multiple-choice questions of this type,if only one must be chosen,$(C)$ is often cited as the most significant anomaly.

Column-$I$	Column-$II$
$(a) IBr$	$(i)$ Orange solid
$(b) ClF_3$	$(ii)$ Yellow-green liquid
$(c) BrF_3$	$(iii)$ Black solid
$(d) ICl_3$	$(iv)$ Colorless gas

Which of the following arrangements does not represent the correct trend indicated against it?

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