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(A) The reaction of $Methylenecyclohexane$ with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.$1$. The double bond attacks the $

Vedclass · Accepted Answer

$1-$(bromomethyl)cyclohexan$-1-$ol

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(A) The reaction of $Methylenecyclohexane$ with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.$1$. The double bond attacks the $Br_2$ molecule to form a cyclic bromonium ion intermediate.$2$. Water $(H_2O)$,acting as a nucleophile,attacks the more substituted carbon of the bromonium ion because it can better stabilize the partial positive charge in the transition state.$3$. This leads to the formation of $1-(bromomethyl)cyclohexan-1-ol$ as the major product.The reaction is:$C_6H_{10}=CH_2 + Br_2 + H_2O \rightarrow C_6H_{10}(OH)(CH_2Br) + HBr$

Identify the product $A$ in the following reaction:
$Methylenecyclohexane \xrightarrow{Br_2 / H_2O} A$

Similar Questions

$CH_3-CH=CH_2 + HBr \xrightarrow{\ \ } .........$,the product formed is

The decreasing order of reactivity of the following alkenes towards $HBr$ addition is:
$(I) \ CH_3-CH=CH_2$
$(II) \ CF_3-CH=CH_2$
$(III) \ MeOCH=CH_2$
$(IV) \ CH_3-CO-CH=CH_2$

Predict the major product $A$ for the following reaction:
$2\text{-methylbuta-1,3-diene} + HBr (1 \text{ eq.}) \xrightarrow{-80^{\circ}C (1,2\text{-addition})} A$

How many products will be formed in the reaction shown below?
$CH_3-CH_2-C(CH_3)=C(CH_3)-CH_2-CH_3 + HBr \xrightarrow{R_2O_2} \text{Products}$

The product of the reaction shown below is:

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Identify the product $A$ in the following reaction:$Methylenecyclohexane \xrightarrow{Br_2 / H_2O} A$