NH_4ClO_4 + HNO_3 (text{dil}) to HClO_4 + (X) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction between ammonium perchlorate and dilute nitric acid is a double displacement reaction:$NH_4ClO_4 + HNO_3 (	ext{dil}) 	o HClO_4 + NH

Vedclass · Accepted Answer

$NH_4NO_3$ and $N_2O$

Vedclass · Answer

(A) The reaction between ammonium perchlorate and dilute nitric acid is a double displacement reaction:$NH_4ClO_4 + HNO_3 (	ext{dil}) 	o HClO_4 + NH_4NO_3$Thus,$(X)$ is $NH_4NO_3$.Upon heating,ammonium nitrate undergoes thermal decomposition:$NH_4NO_3 \xrightarrow{\Delta} N_2O_{(g)} + 2H_2O_{(g)}$Thus,$(Y)$ is $N_2O$.Therefore,$(X)$ and $(Y)$ are $NH_4NO_3$ and $N_2O$ respectively.Hence,option $A$ is correct.

$NH_4ClO_4 + HNO_3 (\text{dil}) \to HClO_4 + (X) \xrightarrow{\Delta} Y_{(g)}$,$(X)$ and $(Y)$ are respectively

Similar Questions

Can $PCl_{5}$ act as an oxidizing as well as a reducing agent? Justify.

Choose the correct stability order of group $13$ elements in their $+1$ oxidation state.

The good reducing nature of $H_3PO_2$ is attributed to the presence of:

Nitrogen is liberated by the thermal decomposition of only:

In the nitrogen family,the $H-M-H$ bond angle in the hydrides $MH_3$ gradually becomes closer to $90^o$ on going from $N$ to $Sb$. This shows that gradually:

Vedclass Test Series

Exam Paper Generator

Online Exam Module