Identify the product B in the following react | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The starting material is $1,4-	ext{cyclohexadiene-1,4-dicarboxylic acid}$.$2$. Treatment with $NaOH$ converts the carboxylic acid groups int

Vedclass · Accepted Answer

$1,4-$cyclohexadiene

Vedclass · Answer

(A) $1$. The starting material is $1,4-	ext{cyclohexadiene-1,4-dicarboxylic acid}$.$2$. Treatment with $NaOH$ converts the carboxylic acid groups into carboxylate ions,forming the disodium salt $A$ $(1,4-	ext{cyclohexadiene-1,4-dicarboxylate})$.$3$. Kolbe electrolysis of the salt of a dicarboxylic acid involves the decarboxylation and the formation of a new carbon-carbon bond between the radical intermediates generated at the anode.$4$. In this specific case,the decarboxylation of the $1,4-	ext{cyclohexadiene-1,4-dicarboxylate}$ dianion leads to the formation of $1,4-	ext{cyclohexadiene}$ as the product $B$ after the loss of $CO_2$ and subsequent radical coupling/disproportionation steps.

Identify the product $B$ in the following reaction sequence:
$1,4-\text{cyclohexadiene-1,4-dicarboxylic acid}$ $\xrightarrow{NaOH} A$ $\xrightarrow{\text{Kolbe electrolysis}} B$

Similar Questions

What is the number of moles of $sp^2$ hybrid carbon atoms in one mole of $hexa-1,4-diyne$?

When a hydrocarbon $A$ undergoes complete combustion,it requires $11$ equivalents of oxygen and produces $4$ equivalents of water. What is the molecular formula of $A$?

Arrange the following compounds in decreasing order of acidic character of $C-H$ bonds.
$CH_2=CH_2, CH_3-CH_3, C_6H_6, CH\equiv CH$

The total number of sigma $(\sigma)$ and pi $(\pi)$ bonds present in $\text{hex}-1-\text{en}-4-\text{yne}$ are respectively:

The compound with molecular formula $C_6H_6$,which gives only one monobromo derivative and takes up four moles of hydrogen per mole for complete hydrogenation,has $................\pi$ electrons.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the product $B$ in the following reaction sequence:$1,4-\text{cyclohexadiene-1,4-dicarboxylic acid}$ $\xrightarrow{NaOH} A$ $\xrightarrow{\text{Kolbe electrolysis}} B$