If 6.5 g of Mg is deposited during the elect | vedclass

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(B) The chemical reaction for the electrolysis of fused $MgCl_2$ is: $MgCl_2 \rightarrow Mg + Cl_2$.According to the stoichiometry,$1 \ mol$ of $Mg$ $

Vedclass · Accepted Answer

$6.067$

Vedclass · Answer

(B) The chemical reaction for the electrolysis of fused $MgCl_2$ is: $MgCl_2 ightarrow Mg + Cl_2$.According to the stoichiometry,$1 \ mol$ of $Mg$ $(24 \ g)$ is produced along with $1 \ mol$ of $Cl_2$ gas.At $STP$,$1 \ mol$ of any gas occupies $22.4 \ L$.Therefore,$24 \ g$ of $Mg$ corresponds to $22.4 \ L$ of $Cl_2$ gas.For $6.5 \ g$ of $Mg$,the volume of $Cl_2$ gas produced is: $V = \frac{22.4 	imes 6.5}{24} \ L$.$V = 6.0666... \ L \approx 6.067 \ L$.

If $6.5 \ g$ of $Mg$ is deposited during the electrolysis of fused $MgCl_2$,what will be the volume of chlorine gas (in $L$) discharged at the electrode at $STP$?

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