CH_3CHO xrightarrow{LiAlH_4} CH_3CH_2OHWhich | vedclass

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(D) The reaction involves the reduction of an aldehyde $(CH_3CHO)$ to a primary alcohol $(CH_3CH_2OH)$ using lithium aluminum hydride $(LiAlH_4)$.$LiA

Vedclass · Accepted Answer

$H^{\ominus}$

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(D) The reaction involves the reduction of an aldehyde $(CH_3CHO)$ to a primary alcohol $(CH_3CH_2OH)$ using lithium aluminum hydride $(LiAlH_4)$.$LiAlH_4$ acts as a source of hydride ions $(H^{\ominus})$.The hydride ion $(H^{\ominus})$ acts as a nucleophile and attacks the electrophilic carbonyl carbon of the aldehyde group.Therefore,the nucleophile added in this reaction is $H^{\ominus}$.

$CH_3CHO \xrightarrow{LiAlH_4} CH_3CH_2OH$
Which nucleophile is added in this reaction?

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$CH_3CHO \xrightarrow{LiAlH_4} CH_3CH_2OH$Which nucleophile is added in this reaction?