${}_{24}Cr$ has configuration $3d^5\,4s^1$ instead of $3d^4\,4s^2$ because of

  • A
    Higher exchange energy
  • B
    Symmetrical distribution of electron
  • C
    $A$ and $B$ both
  • D
    None of these

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Similar Questions

Which of the following sets of quantum numbers is not correct?

Match the $LIST$-$I$ with $LIST$-$II$:
List-$I$ (Orbital)List-$II$ (Radial nodes and nodal plane)
$A$. $2s$$I$. $1$ Radial node + two nodal planes
$B$. $3s$$II$. $1$ Radial node + one nodal plane
$C$. $3p$$III$. $2$ Radial nodes + No nodal plane
$D$. $4d$$IV$. $1$ Radial node + No nodal plane

The probability of finding an electron in the $p_x$ orbital is

The number of correct statements from the following:
$A.$ For $1s$ orbital,the probability density is maximum at the nucleus.
$B.$ For $2s$ orbital,the probability density first increases to maximum and then decreases sharply to zero.
$C.$ Boundary surface diagrams of the orbitals enclose a region of $100\%$ probability of finding the electron.
$D.$ $p$ and $d$-orbitals have $1$ and $2$ angular nodes respectively.
$E.$ Probability density of $p$-orbital is zero at the nucleus.

The five valence electrons of $_{15}P$ are represented as shown in the figure. If the spin quantum number of $B$ and $Z$ is $+1/2$,which of the following groups has three identical quantum numbers?

Difficult
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