The angular momentum of an electron in a 2s o | vedclass

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(C) The angular momentum of an electron is given by the formula: $L = \sqrt{l(l+1)} \frac{h}{2\pi}$,where $l$ is the azimuthal quantum number.For an $

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$4s$

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(C) The angular momentum of an electron is given by the formula: $L = \sqrt{l(l+1)} \frac{h}{2\pi}$,where $l$ is the azimuthal quantum number.For an $s$ orbital,the value of $l$ is $0$.Therefore,the angular momentum of an electron in a $2s$ orbital is $\sqrt{0(0+1)} \frac{h}{2\pi} = 0$.Among the given options,only $s$ orbitals have $l = 0$.Thus,the angular momentum of an electron in a $4s$ orbital is also $\sqrt{0(0+1)} \frac{h}{2\pi} = 0$.Hence,the angular momentum of a $2s$ electron is equal to that of a $4s$ electron.

The angular momentum of an electron in a $2s$ orbital is equal to the angular momentum of an electron in which of the following orbitals?

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