If the quantum number values for the valence | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given quantum numbers $n = 4, l = 0, m = 0$ correspond to the $4s$ orbital. This indicates that the valence electron is in the $4s$ subshell.

Vedclass · Accepted Answer

$19$ or $20$

Vedclass · Answer

(D) The given quantum numbers $n = 4, l = 0, m = 0$ correspond to the $4s$ orbital. This indicates that the valence electron is in the $4s$ subshell. The electronic configuration of the atom must end in $4s^1$ or $4s^2$. If the configuration ends in $4s^1$,the element is Potassium $(K)$,which has an atomic number of $19$. If the configuration ends in $4s^2$,the element is Calcium $(Ca)$,which has an atomic number of $20$. Therefore,the atomic number can be $19$ or $20$.

If the quantum number values for the valence shell electron of an atom are $n = 4, l = 0, m = 0$,then the atomic number of the element could be .........

Similar Questions

Write about the subsidiary quantum number $(l)$.

The rule which states that an electron enters the sub-shell for which the $(n + l)$ value is minimum is known as:

Which of the following $p, d, f$ orbitals are not possible? Why?

Which of the following is the correct electronic configuration of $Cr$ (Chromium)?

For the last electron entering the electronic configuration of potassium $(K)$,the values of $n, l,$ and $m$ are respectively .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module