(C) We know that $1 \, m = 100 \, cm$ and $1 \, m = 10 \, dm$.Therefore,$100 \, cm = 10 \, dm$.This implies $1 \, cm = \frac{10}{100} \, dm = 0.1 \, d

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(C) We know that $1 \, m = 100 \, cm$ and $1 \, m = 10 \, dm$.Therefore,$100 \, cm = 10 \, dm$.This implies $1 \, cm = \frac{10}{100} \, dm = 0.1 \, dm = 10^{-1} \, dm$.Now,convert $5 \times 10^2 \, cm$ to $dm$:$5 \times 10^2 \, cm = 5 \times 10^2 \times 10^{-1} \, dm = 5 \times 10^1 \, dm$.

Class 11 Chemistry Some Basic Concepts of Chemistry Significant figures and Units for measurement

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$5 \times 10^2 \, cm = .......... \, dm$

A
$5 \times 10^2$
B
$10^1$
C
$5 \times 10^1$
D
$10^2$

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Some Basic Concepts of Chemistry

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Significant figures and Units for measurement

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$5 \times 10^2 \, cm = .......... \, dm$

Similar Questions

$4 \ L \ atm$ is equal to (in $cal$)

$3.00 \ kg$ is equal to how many yards? Given: $1 \ kg = 1000 \ m$,$1 \ m = 1.094 \ yards$.

Convert the following into basic units:$(i)$ $28.7\, pm$$(ii)$ $15.15\, pm$$(iii)$ $25365\, mg$

$A$ sample was weighed using two different balances. The results were $(I)$ $3.929 \ g$ and $(II)$ $4.0 \ g$. How would the weight of the sample be reported in $g$?

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Convert the following into basic units:
$(i)$ $28.7\, pm$
$(ii)$ $15.15\, pm$
$(iii)$ $25365\, mg$