How many H atoms are present in 0.46 , g of e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The molar mass of ethanol $[C_2H_5OH]$ is $(2 	imes 12) + (6 	imes 1) + 16 = 46 \, g/mol$.Number of moles of ethanol $= \frac{	ext{Given mass}}

Vedclass · Accepted Answer

$3.6 	imes 10^{22}$

Vedclass · Answer

(A) The molar mass of ethanol $[C_2H_5OH]$ is $(2 	imes 12) + (6 	imes 1) + 16 = 46 \, g/mol$.Number of moles of ethanol $= \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{0.46 \, g}{46 \, g/mol} = 0.01 \, mol = 10^{-2} \, mol$.Each molecule of $C_2H_5OH$ contains $6$ hydrogen atoms.Therefore,the number of moles of $H$ atoms $= 6 	imes 10^{-2} \, mol$.Number of $H$ atoms $= 	ext{moles} 	imes N_A = 6 	imes 10^{-2} 	imes 6.022 	imes 10^{23} \approx 3.61 	imes 10^{22}$ atoms.Thus,the correct option is $A$.

How many $H$ atoms are present in $0.46 \, g$ of ethanol $[C_2H_5OH]$?

Similar Questions

In a sample of $CaCO_3$,there are $3.01 \times 10^{23}$ ions of $Ca^{+2}$ and an equal number of $CO_3^{-2}$ ions. The mass of the sample is = $......$ grams.

Assertion : The number of $O$ atoms in $16 \ g$ of oxygen and $16 \ g$ of ozone is same.
Reason : Each of the species represents $1 \ g$ molecule of oxygen.

The number of water molecules in $1 \, L$ of water is = ............

Calculate the total number of atoms in $5.6 \ L$ of $SO_2$ gas at $NTP$.

How many moles of nitrogen atoms are present in $8 \ g$ of ammonium nitrate (in $mol$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module