If the weight percentage of Se (at. wt. 78.4) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The enzyme contains at least one atom of $Se$.The weight percentage of $Se$ in the enzyme is $0.5 \%$.This means $0.5 \, g$ of $Se$ is present in

Vedclass · Accepted Answer

$1.568 	imes 10^{4}$

Vedclass · Answer

(A) The enzyme contains at least one atom of $Se$.The weight percentage of $Se$ in the enzyme is $0.5 \%$.This means $0.5 \, g$ of $Se$ is present in $100 \, g$ of the enzyme.Therefore,the minimum molecular weight of the enzyme containing $78.4 \, g$ of $Se$ (one mole of $Se$) is:$	ext{Minimum molecular weight} = \frac{78.4 	imes 100}{0.5} \, g/mol$$= 15680 \, g/mol$$= 1.568 	imes 10^{4} \, g/mol$.

If the weight percentage of $Se$ (at. wt. $78.4$) in peroxidase anhydrous enzyme is $0.5 \%$,what is the minimum molecular weight of the enzyme?

Similar Questions

Calculate the mass percentage of different elements present in sodium sulfate $(Na_2SO_4)$.

$A$ compound contains $0.25\%$ of a metal with an atomic weight of $59$. If the compound contains one atom of the metal per molecule,what is the minimum molecular weight of the compound?

The formula of a substance is $(CO)_x$. If its vapor density is $70$,find the value of $x$.

The number of grams of oxygen in $32.2 \ g$ of $Na_2SO_4 \cdot 10H_2O$ is approximately (in $g$)

$C_4H_6O_2$ does not represent :

Vedclass Test Series

Exam Paper Generator

Online Exam Module