An element of mass A_1 , g gives a chloride o | vedclass

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Question

(A) The reaction is: $	ext{Metal} + 	ext{Chlorine} 	o 	ext{Metal Chloride}$.The mass of chlorine combined with $A_1 \, g$ of metal is $(A_2 - A_1)

Vedclass · Accepted Answer

$35.5A_1 / (A_2 - A_1)$

Vedclass · Answer

(A) The reaction is: $	ext{Metal} + 	ext{Chlorine} 	o 	ext{Metal Chloride}$.The mass of chlorine combined with $A_1 \, g$ of metal is $(A_2 - A_1) \, g$.By definition,the equivalent mass of an element is the mass that combines with $35.5 \, g$ of chlorine.Since $(A_2 - A_1) \, g$ of chlorine combines with $A_1 \, g$ of metal,Then $35.5 \, g$ of chlorine will combine with $\frac{A_1 	imes 35.5}{A_2 - A_1} \, g$ of metal.Therefore,the equivalent mass is $\frac{35.5 A_1}{A_2 - A_1}$.

List-$I$ (Substance)	List-$II$ (Equivalent weight)
$A. Na_2CO_3$	$I. M/5$
$B. KMnO_4 / H^+$	$II. M/3$
$C. K_2Cr_2O_7 / H^+$	$III. M/2$
$D. KMnO_4 / H_2O$	$IV. M/6$

An element of mass $A_1 \, g$ gives a chloride of mass $A_2 \, g$. Calculate its equivalent mass.

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