When oxygen is heated in the presence of a ca | vedclass

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Question

(C) The balanced chemical equation for the conversion of oxygen to ozone is:$3O_{2(g)} \longrightarrow 2O_{3(g)}$According to the stoichiometry,$2 	i

Vedclass · Accepted Answer

$480$

Vedclass · Answer

(C) The balanced chemical equation for the conversion of oxygen to ozone is:$3O_{2(g)} \longrightarrow 2O_{3(g)}$According to the stoichiometry,$2 	imes 22.4 \, L$ of $O_3$ is produced by $3 	imes 32 \, g$ of $O_2$.To produce $33.6 \, L$ of $O_3$,the mass of $O_2$ required (assuming $100 \%$ conversion) is:$Mass = \frac{3 	imes 32 	imes 33.6}{2 	imes 22.4} = 72 \, g$Since only $15 \%$ of $O_2$ is converted to $O_3$,the total mass of $O_2$ required is:$Total \, mass = \frac{72 	imes 100}{15} = 480 \, g$

When oxygen is heated in the presence of a catalyst,$15 \%$ of it is converted into ozone. How many grams of oxygen are required to produce $33.6 \, L$ of $O_3$ at $STP$?

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