If equal moles of water and urea are taken in | vedclass

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(C) Let the moles of water and urea be $1$ each.Mass of $1$ mole of water $(H_2O)$ $= 18 \, g$.Mass of $1$ mole of urea $(NH_2CONH_2)$ $= 60 \, g$.Tot

Vedclass · Accepted Answer

$76.92$

Vedclass · Answer

(C) Let the moles of water and urea be $1$ each.Mass of $1$ mole of water $(H_2O)$ $= 18 \, g$.Mass of $1$ mole of urea $(NH_2CONH_2)$ $= 60 \, g$.Total mass of the mixture $= 18 + 60 = 78 \, g$.Percentage by weight of urea $= \frac{	ext{Mass of urea}}{	ext{Total mass}} 	imes 100$.Percentage by weight of urea $= \frac{60}{78} 	imes 100 = 76.92 \%$.

If equal moles of water and urea are taken in a flask,what is the percentage by weight of urea?

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