The cyanide ion $(CN^{-})$ and $N_2$ are isoelectronic. However,in contrast to $CN^{-}$,the $N_2$ molecule is chemically inert due to:

  • A
    $\pi$ bonding
  • B
    Absence of bond polarity
  • C
    Unequal distribution of electrons
  • D
    Presence of more electrons in bonding orbitals

Explore More

Similar Questions

Which of the following molecules has zero dipole moment?

Dipole moment of $HCl = 1.03 \ D$ and $HI = 0.38 \ D$. Bond length of $HCl = 1.3 \ \mathring{A}$ and $HI = 1.6 \ \mathring{A}$. The ratio of the fraction of electric charge,$\delta$,existing on each atom in $HCl$ and $HI$ is:

Which of the following molecules exhibits the lowest dipole moment?

Explain why $O=C=O$ is non-polar while $R-O-R$ is polar?

Give the correct order of initials $T$ or $F$ for the following statements. Use $T$ if the statement is true and $F$ if it is false.
$I. \, (CH_3)_2P(CF_3)_3$ is non-polar and $(CH_3)_3P(CF_3)_2$ is a polar molecule.
$II. \, CH_3 \widehat{P} CH_3$ bond angles are equal in the $(CH_3)_3P(CF_3)_2$ molecule.
$III. \, PF_3$ will be more soluble in a polar solvent than $SiF_4$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo