Which of the following has sp^3 hybridization | vedclass

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(D) To determine the hybridization,we use the formula: $	ext{Steric Number} = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electro

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$XeO_3$

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(D) To determine the hybridization,we use the formula: $	ext{Steric Number} = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.$A) \ BBr_3$: $	ext{Steric Number} = \frac{1}{2} [3 + 3] = 3$ ($sp^2$ hybridization).$B) \ XeF_4$: $	ext{Steric Number} = \frac{1}{2} [8 + 4] = 6$ ($sp^3d^2$ hybridization).$C) \ BCl_3$: $	ext{Steric Number} = \frac{1}{2} [3 + 3] = 3$ ($sp^2$ hybridization).$D) \ XeO_3$: $	ext{Steric Number} = \frac{1}{2} [8 + 0] = 4$ ($sp^3$ hybridization). Note: Oxygen is a divalent atom,so it is not included in the $M$ count.Therefore,$XeO_3$ has $sp^3$ hybridization.

Which of the following has $sp^3$ hybridization?

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