Which of the following has sp^3 hybridization | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the hybridization,we use the formula: $	ext{Steric Number} = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electro

Vedclass · Accepted Answer

$XeO_3$

Vedclass · Answer

(D) To determine the hybridization,we use the formula: $	ext{Steric Number} = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.$A) \ BBr_3$: $	ext{Steric Number} = \frac{1}{2} [3 + 3] = 3$ ($sp^2$ hybridization).$B) \ XeF_4$: $	ext{Steric Number} = \frac{1}{2} [8 + 4] = 6$ ($sp^3d^2$ hybridization).$C) \ BCl_3$: $	ext{Steric Number} = \frac{1}{2} [3 + 3] = 3$ ($sp^2$ hybridization).$D) \ XeO_3$: $	ext{Steric Number} = \frac{1}{2} [8 + 0] = 4$ ($sp^3$ hybridization). Note: Oxygen is a divalent atom,so it is not included in the $M$ count.Therefore,$XeO_3$ has $sp^3$ hybridization.

Which of the following has $sp^3$ hybridization?

Similar Questions

The structure of $IF_{7}$ is

Which of the following molecules has $sp^3d^2$ hybridisation and a square planar shape?

What is the hybridization state of the central atom in the conjugate base of $NH_4^{+}$ ion?

Carbon atoms in diamond are bonded to each other in a configuration:

What is the hybridization and structure of $XeF_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module