0.2 M solution of formic acid is ionized 3.2 | vedclass

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(B) For a weak acid,the ionization constant $K_a$ is given by the formula $K_a = C\alpha^2$,where $C$ is the molar concentration and $\alpha$ is the d

Vedclass · Accepted Answer

$2.1 	imes 10^{-4}$

Vedclass · Answer

(B) For a weak acid,the ionization constant $K_a$ is given by the formula $K_a = C\alpha^2$,where $C$ is the molar concentration and $\alpha$ is the degree of ionization.Given: $C = 0.2 \ M$ and $\alpha = 3.2 \% = 0.032$.Substituting the values: $K_a = 0.2 	imes (0.032)^2$.$K_a = 0.2 	imes 0.001024 = 0.0002048 = 2.048 	imes 10^{-4}$.Rounding to two significant figures,we get $2.1 	imes 10^{-4}$.

$0.2 \ M$ solution of formic acid is ionized $3.2 \%$. Its ionization constant is:

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