If the atomic number of an element is 37,then | vedclass

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(A) The atomic number of the element is $Z = 37$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1$. Since the last el

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$s$ and $1$

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(A) The atomic number of the element is $Z = 37$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1$. Since the last electron enters the $5s$ orbital,the element belongs to the $s$-block. The valence shell configuration is $5s^1$,which indicates it belongs to group $1$ (alkali metals). Therefore,the block is $s$ and the group is $1$.

List-$I$	List-$II$
$A$. $K$	$I$. Thermonuclear reactions
$B$. $KCl$	$II$. Fertilizer
$C$. $KOH$	$III$. Sodium potassium pump
$D$. $Li$	$IV$. Absorbent of $CO_2$

If the atomic number of an element is $37$,then the block and group of that element will be respectively ...

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Match List-$I$ with List-$II$ :
List-$I$ List-$II$
$A$. $K$ $I$. Thermonuclear reactions
$B$. $KCl$ $II$. Fertilizer
$C$. $KOH$ $III$. Sodium potassium pump
$D$. $Li$ $IV$. Absorbent of $CO_2$

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Select the correct statement from the following.

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