The values of Delta _iH_1, Delta _iH_2, Delta | vedclass

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(B) The successive ionization energies are given as: $\Delta _iH_1 = 7.5 \ eV$,$\Delta _iH_2 = 25.6 \ eV$,$\Delta _iH_3 = 48.6 \ eV$,and $\Delta _iH_4

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$1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^1$

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(B) The successive ionization energies are given as: $\Delta _iH_1 = 7.5 \ eV$,$\Delta _iH_2 = 25.6 \ eV$,$\Delta _iH_3 = 48.6 \ eV$,and $\Delta _iH_4 = 170.6 \ eV$. $A$ large jump in ionization energy indicates the removal of an electron from a stable,fully-filled or half-filled shell (noble gas configuration). Here,the jump from $\Delta _iH_3$ $(48.6 \ eV)$ to $\Delta _iH_4$ $(170.6 \ eV)$ is very large,which suggests that the atom has $3$ valence electrons. Among the given options,the configuration $1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^1$ (Aluminum,$Z=13$) has $3$ valence electrons in the $3s$ and $3p$ orbitals. Therefore,the correct electronic configuration is $1s^2 \ 2s^2 \ 2p^6 \ 3s^2 \ 3p^1$.

$I.P.$ \text{ Trend}	Reason
$A$. $N > O$	Half-filled configuration
$B$. $Zr < Hf$	Lanthanide contraction
$C$. $Na > K$	$Z_{eff}$
$D$. $Al < Ga$	Transition contraction

The values of $\Delta _iH_1, \Delta _iH_2, \Delta _iH_3$,and $\Delta _iH_4$ for an atom are $7.5 \ eV, 25.6 \ eV, 48.6 \ eV$,and $170.6 \ eV$ respectively. Determine the electronic configuration of the atom.

Similar Questions

Which of the following statements is incorrect?

The correct order of ionisation energy of $C$,$N$,$O$,and $F$ is

The first ionization potentials $\left( eV \right)$ of $Be$ and $B$ respectively are:

Identify the incorrect match regarding Ionization Potential $(I.P.)$ trends:

$I.P.$ \text{ Trend} Reason

$A$. $N > O$ Half-filled configuration

$B$. $Zr < Hf$ Lanthanide contraction

$C$. $Na > K$ $Z_{eff}$

$D$. $Al < Ga$ Transition contraction

The increasing order of the first ionization enthalpies of the elements $B$,$P$,$S$ and $F$ (lowest first) is:

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