(i) , Al , xrightarrow{N_2} , A (ii) , Al , x | vedclass

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(C) The reaction of $Al$ with $N_2$ at high temperature gives aluminum nitride: $2Al + N_2 \rightarrow 2AlN \, (A)$ Hydrolysis of $AlN$ gives ammonia:

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$NH_3, \, CH_4$

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(C) The reaction of $Al$ with $N_2$ at high temperature gives aluminum nitride: $2Al + N_2 \rightarrow 2AlN \, (A)$ Hydrolysis of $AlN$ gives ammonia: $AlN + 3H_2O \rightarrow Al(OH)_3 + NH_3 \uparrow$ The reaction of $Al$ with $C$ at high temperature gives aluminum carbide: $4Al + 3C \rightarrow Al_4C_3 \, (B)$ Hydrolysis of $Al_4C_3$ gives methane: $Al_4C_3 + 12H_2O \rightarrow 4Al(OH)_3 + 3CH_4 \uparrow$ Therefore,$A$ gives $NH_3$ and $B$ gives $CH_4$.

$(i) \, Al \, \xrightarrow{N_2} \, A$
$(ii) \, Al \, \xrightarrow{C} \, B$
Here $A$ and $B$ on hydrolysis respectively give:

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$(i) \, Al \, \xrightarrow{N_2} \, A$ $(ii) \, Al \, \xrightarrow{C} \, B$ Here $A$ and $B$ on hydrolysis respectively give: