C_6H_5-CH_3 xrightarrow{KMnO_4} A xrightarrow | vedclass

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(C) Step $1$: Oxidation of toluene $(C_6H_5-CH_3)$ with alkaline $KMnO_4$ gives benzoic acid $(C_6H_5COOH)$ as product $A$.Step $2$: Decarboxylation o

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$C_6H_6$

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(C) Step $1$: Oxidation of toluene $(C_6H_5-CH_3)$ with alkaline $KMnO_4$ gives benzoic acid $(C_6H_5COOH)$ as product $A$.Step $2$: Decarboxylation of sodium benzoate $(C_6H_5COONa)$ with soda lime $(NaOH + CaO)$ at high temperature $(\Delta)$ yields benzene $(C_6H_6)$ as product $B$.Reaction sequence: $C_6H_5-CH_3$ $\xrightarrow{KMnO_4} C_6H_5COOH$ $\xrightarrow{NaOH} C_6H_5COONa$ $\xrightarrow{NaOH + CaO, \Delta} C_6H_6$.

$C_6H_5-CH_3$ $\xrightarrow{KMnO_4} A$ $\xrightarrow[\Delta]{NaOH + CaO} B$, product $B$ is

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