$P_4O_{10}$ reacts with $HNO_3$ to give:

  • A
    $N_2O, H_3PO_2$
  • B
    $N_2O_3, H_3PO_4$
  • C
    $NO_2, HPO_3$
  • D
    $N_2O_5, HPO_3$

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