CH_3-CH_2-I xrightarrow{NaCN} A xrightarrow[P | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: $CH_3-CH_2-I$ reacts with $NaCN$ to form $CH_3-CH_2-CN$ $(A)$ via nucleophilic substitution.Step $2$: Partial hydrolysis of $CH_3-CH_2-C

Vedclass · Accepted Answer

$CH_3-CH_2-NH_2$

Vedclass · Answer

(C) Step $1$: $CH_3-CH_2-I$ reacts with $NaCN$ to form $CH_3-CH_2-CN$ $(A)$ via nucleophilic substitution.Step $2$: Partial hydrolysis of $CH_3-CH_2-CN$ $(A)$ in the presence of $\Theta OH$ yields $CH_3-CH_2-CONH_2$ $(B)$ (propanamide).Step $3$: The reaction of $CH_3-CH_2-CONH_2$ $(B)$ with $Br_2$ and $NaOH$ is the Hofmann bromamide degradation reaction,which converts an amide into a primary amine with one carbon atom less.Step $4$: The product $C$ is $CH_3-CH_2-NH_2$ (ethanamine).

$CH_3-CH_2-I$ $\xrightarrow{NaCN} A$ $\xrightarrow[Partial \ hydrolysis]{\Theta OH} B$ $\xrightarrow[Br_2]{NaOH} C$. Product $C$ is

Similar Questions

Which of the following is $NOT$ a correct method for the preparation of benzylamine $(C_6H_5CH_2NH_2)$ from cyanobenzene $(C_6H_5CN)$?

Which of the following nitrogen compounds gives a primary amine upon reaction with $Br_2$ and strong $KOH$ (Hofmann bromamide degradation reaction)?

The Mendius reaction is involved in the reduction of which of the following?

Find the suitable method from the following to prepare primary amines without the loss of carbons.

Consider the following sequence of reactions:
$PhCOOH$ $\xrightarrow[2. NH_3]{1. PCl_5} A$ $\xrightarrow[2. H_2/Ni]{1. P_4O_{10}, \text{heat}} B.$
The final product $(B)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module