HO-CH_2-C(=O)-CH(OH)-CH_2-OH xrightarrow{HIO_ | vedclass

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(D) $HIO_4$ (Periodic acid) cleaves the $C-C$ bond between adjacent carbons having $-OH$ or $>C=O$ groups.$HO-CH_2-C(=O)-CH(OH)-CH_2-OH \xrightarrow{3

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(D) $HIO_4$ (Periodic acid) cleaves the $C-C$ bond between adjacent carbons having $-OH$ or $>C=O$ groups.$HO-CH_2-C(=O)-CH(OH)-CH_2-OH \xrightarrow{3HIO_4} 2H_2C=O + CO_2 + HCOOH$.$1.$ Terminal $-CH_2OH$ groups are oxidized to formaldehyde $(H_2C=O)$.$2.$ The internal $-C(=O)-$ group is oxidized to $CO_2$.$3.$ The internal $-CH(OH)-$ group is oxidized to formic acid $(HCOOH)$.Therefore,all the given products are formed.

$HO-CH_2-C(=O)-CH(OH)-CH_2-OH \xrightarrow{HIO_4} \text{Product obtained is}$

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