2 mol of zinc is dissolved in HCl at 25 ^ci | vedclass

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(B) The chemical reaction is: $Zn(s) + 2HCl(aq) \rightarrow ZnCl_2(aq) + H_2(g)$.The number of moles of gas produced is $\Delta n_g = 1 \ mol$ (for $1

Vedclass · Accepted Answer

$- 4.955 \ kJ$

Vedclass · Answer

(B) The chemical reaction is: $Zn(s) + 2HCl(aq) ightarrow ZnCl_2(aq) + H_2(g)$.The number of moles of gas produced is $\Delta n_g = 1 \ mol$ (for $1 \ mol$ of $Zn$).For $2 \ mol$ of $Zn$,$\Delta n_g = 2 \ mol$.The work done in an open vessel is given by $W = - P \Delta V = - \Delta n_g RT$.Given $T = 25^{\circ} C = 298 \ K$ and $R = 8.314 \ J \cdot mol^{-1} \cdot K^{-1}$.$W = - 2 	imes 8.314 	imes 298 = - 4958.7 \ J = - 4.959 \ kJ$.Rounding to the nearest value,the work done is $- 4.955 \ kJ$.

$2 \ mol$ of zinc is dissolved in $HCl$ at $25 \ ^\circ C$. The work done in an open vessel is:

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