For a reaction,doubling the concentration of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The half-life period $(t_{1/2})$ of a reaction of order $n$ is related to the initial concentration $([A]_0)$ as: $t_{1/2} \propto [A]_0^{1-n}$.Gi

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) The half-life period $(t_{1/2})$ of a reaction of order $n$ is related to the initial concentration $([A]_0)$ as: $t_{1/2} \propto [A]_0^{1-n}$.Given that doubling the concentration $([A]_0 	o 2[A]_0)$ doubles the half-life $(t_{1/2} 	o 2t_{1/2})$,we have:$2t_{1/2} \propto (2[A]_0)^{1-n}$.Dividing the two relations: $2 = 2^{1-n}$.This implies $1 = 1 - n$,so $n = 0$.Therefore,the reaction is of zero order.

For a reaction,doubling the concentration of the reactant doubles the half-life period. What is the order of the reaction?

Similar Questions

Which of the following graphs most appropriately represents a zero order reaction?

The unit of rate constant for a zero order reaction is

$2A \xrightarrow{k} B$ is a zero-order reaction, where $k = 1.0 \text{ mol L}^{-1} \text{ min}^{-1}$. If the initial concentration of $A$ is $2 \text{ M}$, then the time taken to complete $75\%$ of the reaction will be (in $\text{ min}$)

Which of the following reactions end in finite time?

$A$ zero-order reaction,$A \rightarrow \text{Product}$,with an initial concentration $[A]_0$ has a half-life of $0.2 \ s$. If one starts with the concentration $2[A]_0$,then the half-life is $.... \ s$

Vedclass Test Series

Exam Paper Generator

Online Exam Module