For the reaction X rightleftharpoons Y,the pr | vedclass

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(C) According to the Arrhenius equation,the rate constant $k$ is given by $k = A e^{-E_a/RT}$.For the forward reaction: $k_f = A_f e^{-E_{af}/RT}$.For

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$e^{-\Delta E/RT}$

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(C) According to the Arrhenius equation,the rate constant $k$ is given by $k = A e^{-E_a/RT}$.For the forward reaction: $k_f = A_f e^{-E_{af}/RT}$.For the backward reaction: $k_b = A_b e^{-E_{ab}/RT}$.Given that the pre-exponential factors are equal,$A_f = A_b = A$.The equilibrium constant $K_c$ is defined as $K_c = \frac{k_f}{k_b}$.Substituting the expressions: $K_c = \frac{A e^{-E_{af}/RT}}{A e^{-E_{ab}/RT}} = e^{(E_{ab} - E_{af})/RT}$.Since $\Delta E = E_{af} - E_{ab}$,it follows that $E_{ab} - E_{af} = -\Delta E$.Therefore,$K_c = e^{-\Delta E/RT}$.

For the reaction $X \rightleftharpoons Y$,the pre-exponential factors for the forward and backward reactions are equal. What will be the equilibrium constant of the reaction?

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