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(C) The reaction of $AgNO_3$ with the aqueous solution of a coordination compound precipitates only the chloride ions $(Cl^-)$ that are present outsid

Vedclass · Accepted Answer

$[CrCl_2(H_2O)_4]Cl \cdot 2H_2O$

Vedclass · Answer

(C) The reaction of $AgNO_3$ with the aqueous solution of a coordination compound precipitates only the chloride ions $(Cl^-)$ that are present outside the coordination sphere (ionizable chloride).Given that $1/3$ of the total chlorine is precipitated,it means that out of $3$ chlorine atoms,only $1$ is present outside the coordination sphere.Therefore,the formula must be of the type $[CrCl_2(H_2O)_4]Cl \cdot 2H_2O$.In this structure,there is $1$ ionizable $Cl^-$ ion,which reacts with $AgNO_3$ to form $AgCl$ precipitate.

If $1/3$ of the total chlorine in the compound $CrCl_3 \cdot 6H_2O$ is precipitated by adding $AgNO_3$ to its aqueous solution,what is the possible structure of the compound?

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