Which of the following complexes has a square | vedclass

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(D) $1$. In $[Ni(CO)_4]$,$Ni$ is in $0$ oxidation state. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$2$. In $[NiCl_4]^{2-}$

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$[Cu(NH_3)_4]^{2+}$

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(D) $1$. In $[Ni(CO)_4]$,$Ni$ is in $0$ oxidation state. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$2$. In $[NiCl_4]^{2-}$,$Ni$ is in $+2$ oxidation state $(3d^8)$. $Cl^-$ is a weak field ligand,so it undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$3$. In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in $+2$ oxidation state $(3d^8)$. It undergoes $sp^3d^2$ hybridization,resulting in an octahedral geometry.$4$. In $[Cu(NH_3)_4]^{2+}$,$Cu$ is in $+2$ oxidation state $(3d^9)$. The unpaired electron is in the $4p_z$ orbital,and the complex undergoes $dsp^2$ hybridization,resulting in a square planar geometry.

Which of the following complexes has a square planar geometry?

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