Which of the following complexes is colorless | vedclass

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(B) To determine if a complex is colorless,we check the electronic configuration of the central metal ion. $A$ complex is colorless if the metal ion h

Vedclass · Accepted Answer

$Na_2[CdCl_4]$

Vedclass · Answer

(B) To determine if a complex is colorless,we check the electronic configuration of the central metal ion. $A$ complex is colorless if the metal ion has a $d^{10}$ configuration (no unpaired electrons and no $d-d$ transitions) or a $d^0$ configuration.$1$. In $Na_2[CuCl_4]$,$Cu$ is in the $+2$ oxidation state $(Cu^{2+})$,which is $3d^9$. It has one unpaired electron and is colored.$2$. In $Na_2[CdCl_4]$,$Cd$ is in the $+2$ oxidation state $(Cd^{2+})$. The electronic configuration of $Cd$ is $[Kr] 4d^{10} 5s^2$. Thus,$Cd^{2+}$ is $[Kr] 4d^{10}$. Since the $d$-subshell is completely filled,no $d-d$ transition is possible,making it colorless.$3$. In $K_4[Fe(CN)_6]$,$Fe$ is in the $+2$ oxidation state $(Fe^{2+})$,which is $3d^6$. It is colored.$4$. In $K_3[Fe(CN)_6]$,$Fe$ is in the $+3$ oxidation state $(Fe^{3+})$,which is $3d^5$. It is colored.Therefore,the correct option is $B$.

Which of the following complexes is colorless?

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