The reaction of an alkyl bromide (X) with Na | vedclass

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(D) The Wurtz reaction involves the coupling of two alkyl halide molecules to form a symmetric alkane: $2R-X + 2Na \rightarrow R-R + 2NaX$. Given the

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$CH_3(CH_2)_2CH(Br)CH_2CH_3$

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(D) The Wurtz reaction involves the coupling of two alkyl halide molecules to form a symmetric alkane: $2R-X + 2Na \rightarrow R-R + 2NaX$. Given the product is $4, 5-$diethyl octane,which has the structure $CH_3-CH_2-CH_2-CH(C_2H_5)-CH(C_2H_5)-CH_2-CH_2-CH_3$. Splitting this molecule at the center (between $C_4$ and $C_5$),we get two identical fragments: $CH_3-CH_2-CH_2-CH(C_2H_5)-$. Replacing the radical with a bromine atom,we get the alkyl bromide $(X)$ as $CH_3-CH_2-CH_2-CH(Br)-CH_2-CH_3$. This corresponds to $3-$bromohexane,which is $CH_3-CH_2-CH_2-CH(Br)CH_2CH_3$.

The reaction of an alkyl bromide $(X)$ with $Na$ in dry ether gives $4, 5-$diethyl octane. Then $(X)$ is:

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