A hydrocarbon with molecular formula C_6H_{10 | vedclass

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(C) $1$. The molecular formula $C_6H_{10}$ corresponds to the general formula $C_nH_{2n-2}$,which indicates the presence of either one triple bond or

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Cyclohexene

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(C) $1$. The molecular formula $C_6H_{10}$ corresponds to the general formula $C_nH_{2n-2}$,which indicates the presence of either one triple bond or two double bonds or a ring with one double bond.$2$. The hydrocarbon absorbs only one molecule of $H_2$,which means it contains only one double bond.$3$. Ozonolysis of the hydrocarbon yields $OHC-CH_2-CH_2-CH_2-CH_2-CHO$,which is hexanedial $(CHO-(CH_2)_4-CHO)$.$4$. Since the product is a straight-chain dialdehyde with $6$ carbon atoms,the original hydrocarbon must be a cyclic compound with $6$ carbon atoms and one double bond.$5$. Therefore,the hydrocarbon is cyclohexene.

$A$ hydrocarbon with molecular formula $C_6H_{10}$ absorbs only one molecule of $H_2$ upon hydrogenation. Ozonolysis of the hydrocarbon yields $OHC-CH_2-CH_2-CH_2-CH_2-CHO$. The hydrocarbon is:

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