What is the product obtained when 2-methylpro | vedclass

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(C) The reaction of an alkene with an acyl chloride in the presence of a Lewis acid like anhydrous $ZnCl_2$ is an electrophilic addition reaction (spe

Vedclass · Accepted Answer

$(CH_3)_2C(Cl)-CH_2COCH_3$

Vedclass · Answer

(C) The reaction of an alkene with an acyl chloride in the presence of a Lewis acid like anhydrous $ZnCl_2$ is an electrophilic addition reaction (specifically,a Friedel-Crafts type acylation of the alkene).In this reaction,the acetyl cation $(CH_3CO^+)$ acts as an electrophile and attacks the double bond of $2-$methylpropene.Following the attack,the chloride ion $(Cl^-)$ adds to the carbocation formed,resulting in a $\beta-$chloro ketone.For $2-$methylpropene $((CH_3)_2C=CH_2)$,the reaction proceeds as follows:$(CH_3)_2C=CH_2 + CH_3COCl \xrightarrow{ZnCl_2} (CH_3)_2C(Cl)-CH_2COCH_3$.Thus,the correct product is $1-$chloro$-4,4-$dimethylpentan$-2-$one,which corresponds to option $C$.

What is the product obtained when $2-$methylpropene is heated with acetyl chloride in the presence of anhydrous $ZnCl_2$?

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