The conversion of 2,3-dibromobutane to 2-bute | vedclass

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(D) The reaction of $2,3-$dibromobutane with $Zn$ dust in alcohol is a debromination reaction: $CH_3-CH(Br)-CH(Br)-CH_3 + Zn \rightarrow CH_3-CH=CH-CH

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Both $(A)$ and $(B)$

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(D) The reaction of $2,3-$dibromobutane with $Zn$ dust in alcohol is a debromination reaction: $CH_3-CH(Br)-CH(Br)-CH_3 + Zn \rightarrow CH_3-CH=CH-CH_3 + ZnBr_2$. In this reaction,two bromine atoms are removed from adjacent carbon atoms,which is known as $\beta-$elimination. Additionally,the oxidation state of $Zn$ changes from $0$ to $+2$ and the bromine atoms change from $-1$ to $-1$ (in $ZnBr_2$),but the organic molecule undergoes a redox process where the carbon atoms change their oxidation states. Thus,it is both a redox reaction and a $\beta-$elimination reaction.

The conversion of $2,3-$dibromobutane to $2-$butene in the presence of $Zn$ is an example of ...........

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