CH_3-C equiv C-CH_3 xrightarrow{NaNH_2} X. Wh | vedclass

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Question

(D) The reactant $CH_3-C \equiv C-CH_3$ is an internal alkyne (but$-2-$yne).$NaNH_2$ is a strong base,but it requires an acidic terminal hydrogen (alk

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No reaction

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(D) The reactant $CH_3-C \equiv C-CH_3$ is an internal alkyne (but$-2-$yne).$NaNH_2$ is a strong base,but it requires an acidic terminal hydrogen (alkyne hydrogen) to perform deprotonation or isomerization.Since but$-2-$yne does not have any terminal acidic hydrogen atoms,it does not react with $NaNH_2$ under standard conditions.Therefore,no reaction occurs.

$CH_3-C \equiv C-CH_3$ $\xrightarrow{NaNH_2}$ $X$. What is $X$?

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