What will be X in the following reaction?{C_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of ethyne $({C_2}{H_2})$ with water in the presence of $HgSO_4$ and $H_2SO_4$ is a hydration reaction.First,the addition of water to

Vedclass · Accepted Answer

$CH_2 = CH - OH$

Vedclass · Answer

(D) The reaction of ethyne $({C_2}{H_2})$ with water in the presence of $HgSO_4$ and $H_2SO_4$ is a hydration reaction.First,the addition of water to the triple bond occurs to form an unstable enol intermediate,which is $CH_2 = CH - OH$ (vinyl alcohol).This enol intermediate undergoes tautomerization to form the more stable carbonyl compound,acetaldehyde $(CH_3CHO)$.Therefore,$X$ is $CH_2 = CH - OH$.

What will be $X$ in the following reaction?
${C_2}{H_2} \xrightarrow[{HgSO_4 / H_2SO_4, 60^{\circ}C}]{{H_2O}} X \rightleftharpoons CH_3CHO$

Similar Questions

$A$ $\xrightarrow[1\% \ HgSO_4]{20\% \ H_2SO_4} B$ $\xrightarrow{I_2 + NaOH} C + C_6H_5COONa$. The reactant $A$ is

The major product obtained from the following reaction is

Distinction between $pent-1-ene$ and $pent-1-yne$ is done by:

Hydration of propyne results in the formation of.......

The major product $(A)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What will be $X$ in the following reaction?${C_2}{H_2} \xrightarrow[{HgSO_4 / H_2SO_4, 60^{\circ}C}]{{H_2O}} X \rightleftharpoons CH_3CHO$