One mole of 1, 2-dibromopropane is reacted wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of $1, 2-$dibromopropane $(CH_3-CHBr-CH_2Br)$ with $NaNH_2$ (a strong base) leads to dehydrohalogenation to form propyne $(CH_3-C \eq

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The reaction of $1, 2-$dibromopropane $(CH_3-CHBr-CH_2Br)$ with $NaNH_2$ (a strong base) leads to dehydrohalogenation to form propyne $(CH_3-C \equiv CH)$.This process requires $2$ moles of $NaNH_2$ to remove two molecules of $HBr$.The resulting propyne is then treated with a base to form the sodium propynide $(CH_3-C \equiv C^-Na^+)$,which requires an additional $1$ mole of $NaNH_2$.Finally,the sodium propynide reacts with ethyl bromide $(CH_3CH_2Br)$ via an $S_N2$ mechanism to form pentyne $(CH_3-C \equiv C-CH_2CH_3)$.Total moles of $NaNH_2$ required: $2$ (for dehydrohalogenation) $+ 1$ (for deprotonation) $= 3$ moles.

One mole of $1, 2-$dibromopropane is reacted with $x$ moles of $NaNH_2$ followed by treatment with ethyl bromide to yield a pentyne. What is the value of $x$?

Similar Questions

The triple bond of ethyne is made of,or the cylindrical shape of an alkyne is due to:

In the reaction
$R - C \equiv C - R \xrightarrow{Pd + CaCO_3} B$
$R - C \equiv C - R \xrightarrow{Na + liq. NH_3} A$
$A$ and $B$ are geometrical isomers. Then:

Give the main product of the following reactions:
$(i)$ $1,1,2,2-$tetrabromopropane + zinc powder in methanol.
$(ii)$ Reaction occurring on passing hydrogen gas through carbon electrodes at high temperature in an electric arc.

Which of the following reactions will yield $2, 2-$dibromopropane?

$A$ compound $C_5H_8$ gives a white precipitate with ammoniacal $AgNO_3$. It yields $(CH_3)_2CHCOOH$ upon oxidation with hot alkaline $KMnO_4$. The compound is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module