What will be $C$ in the following reaction?
$C_6H_5CH_3$ $\xrightarrow{\text{Oxidation}} A$ $\xrightarrow{NaOH} B$ $\xrightarrow[\Delta]{\text{sodalime}} C$

Among the following,the aromatic compound is:

Given below are two statements:
Statement $I$: Nitration of benzene involves the following step:
$H-O^+(H)-NO_2 \rightleftharpoons H_2O + NO_2^+$
Statement $II$: Use of Lewis base promotes the electrophilic substitution of benzene.
In the light of the above statements,choose the most appropriate answer from the options given below:

Which compound among the following is most reactive towards electrophilic reagents?

The products $P$ and $Q$ in the following sequence of reactions are:
$p$-Methylanisole $\xrightarrow{Li, EtOH, NH_3(l)} P$ $\xrightarrow[(ii) -78^{\circ}C, Me_2S]{(i) O_3 (1 \text{ equiv.})} Q$

The order of decreasing reactivity towards an electrophilic reagent,for the following compounds,is:
$(i) \text{ Benzene} \quad (ii) \text{ Toluene} \quad (iii) \text{ Chlorobenzene} \quad (iv) \text{ Phenol}$