The reaction of benzene with a mixture of concentrated $HNO_3$ and concentrated $H_2SO_4$,followed by treatment with $Cl_2 / FeCl_3$,gives:

  • A
    $3-$chloro$-1-$nitrobenzene
  • B
    $2-$chloro$-1-$nitrobenzene
  • C
    $4-$chloro$-1-$nitrobenzene
  • D
    $A$ mixture of $2-$chloro and $4-$chloro$-1-$nitrobenzene

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